y^2+2y+232=0

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Solution for y^2+2y+232=0 equation:


Simplifying
y2 + 2y + 232 = 0

Reorder the terms:
232 + 2y + y2 = 0

Solving
232 + 2y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-232' to each side of the equation.
232 + 2y + -232 + y2 = 0 + -232

Reorder the terms:
232 + -232 + 2y + y2 = 0 + -232

Combine like terms: 232 + -232 = 0
0 + 2y + y2 = 0 + -232
2y + y2 = 0 + -232

Combine like terms: 0 + -232 = -232
2y + y2 = -232

The y term is 2y.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2y + 1 + y2 = -232 + 1

Reorder the terms:
1 + 2y + y2 = -232 + 1

Combine like terms: -232 + 1 = -231
1 + 2y + y2 = -231

Factor a perfect square on the left side:
(y + 1)(y + 1) = -231

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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